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10k^2+3k=k
We move all terms to the left:
10k^2+3k-(k)=0
We add all the numbers together, and all the variables
10k^2+2k=0
a = 10; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·10·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*10}=\frac{-4}{20} =-1/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*10}=\frac{0}{20} =0 $
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